y^2+4y+4x+20=0

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Solution for y^2+4y+4x+20=0 equation:


Simplifying
y2 + 4y + 4x + 20 = 0

Reorder the terms:
20 + 4x + 4y + y2 = 0

Solving
20 + 4x + 4y + y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + 4x + 4y + -20 + y2 = 0 + -20

Reorder the terms:
20 + -20 + 4x + 4y + y2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + 4x + 4y + y2 = 0 + -20
4x + 4y + y2 = 0 + -20

Combine like terms: 0 + -20 = -20
4x + 4y + y2 = -20

Add '-4y' to each side of the equation.
4x + 4y + -4y + y2 = -20 + -4y

Combine like terms: 4y + -4y = 0
4x + 0 + y2 = -20 + -4y
4x + y2 = -20 + -4y

Add '-1y2' to each side of the equation.
4x + y2 + -1y2 = -20 + -4y + -1y2

Combine like terms: y2 + -1y2 = 0
4x + 0 = -20 + -4y + -1y2
4x = -20 + -4y + -1y2

Divide each side by '4'.
x = -5 + -1y + -0.25y2

Simplifying
x = -5 + -1y + -0.25y2

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